4x-(2x-10)=10-6(x+12)

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Solution for 4x-(2x-10)=10-6(x+12) equation: 



4x-(2x-10)=10-6(x+12)

We move all terms to the left:

4x-(2x-10)-(10-6(x+12))=0

We get rid of parentheses

4x-2x-(10-6(x+12))+10=0



We calculate terms in parentheses: -(10-6(x+12)), so:

10-6(x+12)

determiningTheFunctionDomain
-6(x+12)+10

We multiply parentheses

-6x-72+10

We add all the numbers together, and all the variables

-6x-62

Back to the equation:

-(-6x-62)



We add all the numbers together, and all the variables

2x-(-6x-62)+10=0

We get rid of parentheses

2x+6x+62+10=0

We add all the numbers together, and all the variables

8x+72=0

We move all terms containing x to the left, all other terms to the right

8x=-72

x=-72/8

x=-9

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