4x-(2x-3)=3x-(3x-4)

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Solution for 4x-(2x-3)=3x-(3x-4) equation: 



4x-(2x-3)=3x-(3x-4)

We move all terms to the left:

4x-(2x-3)-(3x-(3x-4))=0

We get rid of parentheses

4x-2x-(3x-(3x-4))+3=0



We calculate terms in parentheses: -(3x-(3x-4)), so:

3x-(3x-4)

We get rid of parentheses

3x-3x+4

We add all the numbers together, and all the variables

4

Back to the equation:

-(4)



We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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