4x-(3+3x)=2(6+x)

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Solution for 4x-(3+3x)=2(6+x) equation: 



4x-(3+3x)=2(6+x)

We move all terms to the left:

4x-(3+3x)-(2(6+x))=0

We add all the numbers together, and all the variables

4x-(3x+3)-(2(x+6))=0

We get rid of parentheses

4x-3x-(2(x+6))-3=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

x-(2x+12)-3=0

We get rid of parentheses

x-2x-12-3=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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