4x-(3+x)=2(x+1)

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Solution for 4x-(3+x)=2(x+1) equation: 



4x-(3+x)=2(x+1)

We move all terms to the left:

4x-(3+x)-(2(x+1))=0

We add all the numbers together, and all the variables

4x-(x+3)-(2(x+1))=0

We get rid of parentheses

4x-x-(2(x+1))-3=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

3x-(2x+2)-3=0

We get rid of parentheses

3x-2x-2-3=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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