4x-(3-x)=6+x-(2x-3)

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Solution for 4x-(3-x)=6+x-(2x-3) equation: 



4x-(3-x)=6+x-(2x-3)

We move all terms to the left:

4x-(3-x)-(6+x-(2x-3))=0

We add all the numbers together, and all the variables

4x-(-1x+3)-(6+x-(2x-3))=0

We get rid of parentheses

4x+1x-(6+x-(2x-3))-3=0



We calculate terms in parentheses: -(6+x-(2x-3)), so:

6+x-(2x-3)

determiningTheFunctionDomain
x-(2x-3)+6

We get rid of parentheses

x-2x+3+6

We add all the numbers together, and all the variables

-1x+9

Back to the equation:

-(-1x+9)



We add all the numbers together, and all the variables

5x-(-1x+9)-3=0

We get rid of parentheses

5x+1x-9-3=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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