4x-(3-x)=7(x-3)+10=

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Solution for 4x-(3-x)=7(x-3)+10= equation: 



4x-(3-x)=7(x-3)+10=

We move all terms to the left:

4x-(3-x)-(7(x-3)+10)=0

We add all the numbers together, and all the variables

4x-(-1x+3)-(7(x-3)+10)=0

We get rid of parentheses

4x+1x-(7(x-3)+10)-3=0



We calculate terms in parentheses: -(7(x-3)+10), so:

7(x-3)+10

We multiply parentheses

7x-21+10

We add all the numbers together, and all the variables

7x-11

Back to the equation:

-(7x-11)



We add all the numbers together, and all the variables

5x-(7x-11)-3=0

We get rid of parentheses

5x-7x+11-3=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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