4x-(3x+1)=8+6(x-1)

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Solution for 4x-(3x+1)=8+6(x-1) equation: 



4x-(3x+1)=8+6(x-1)

We move all terms to the left:

4x-(3x+1)-(8+6(x-1))=0

We get rid of parentheses

4x-3x-(8+6(x-1))-1=0



We calculate terms in parentheses: -(8+6(x-1)), so:

8+6(x-1)

determiningTheFunctionDomain
6(x-1)+8

We multiply parentheses

6x-6+8

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

x-(6x+2)-1=0

We get rid of parentheses

x-6x-2-1=0

We add all the numbers together, and all the variables

-5x-3=0

We move all terms containing x to the left, all other terms to the right

-5x=3

x=3/-5

x=-3/5

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