4x-(3x-(x+1)-6)=

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Solution for 4x-(3x-(x+1)-6)= equation: 



4x-(3x-(x+1)-6)=

We move all terms to the left:

4x-(3x-(x+1)-6)-()=0

We add all the numbers together, and all the variables

4x-(3x-(x+1)-6)=0



We calculate terms in parentheses: -(3x-(x+1)-6), so:

3x-(x+1)-6

We get rid of parentheses

3x-x-1-6

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We get rid of parentheses

4x-2x+7=0

We add all the numbers together, and all the variables

2x+7=0

We move all terms containing x to the left, all other terms to the right

2x=-7

x=-7/2

x=-3+1/2

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