4x-(5x+1)=8x+2(x-3)

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Solution for 4x-(5x+1)=8x+2(x-3) equation: 



4x-(5x+1)=8x+2(x-3)

We move all terms to the left:

4x-(5x+1)-(8x+2(x-3))=0

We get rid of parentheses

4x-5x-(8x+2(x-3))-1=0



We calculate terms in parentheses: -(8x+2(x-3)), so:

8x+2(x-3)

We multiply parentheses

8x+2x-6

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We add all the numbers together, and all the variables

-1x-(10x-6)-1=0

We get rid of parentheses

-1x-10x+6-1=0

We add all the numbers together, and all the variables

-11x+5=0

We move all terms containing x to the left, all other terms to the right

-11x=-5

x=-5/-11

x=5/11

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