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4x-1/6x+2=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
4x*6x+2*6x-1=0
Wy multiply elements
24x^2+12x-1=0
a = 24; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·24·(-1)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{15}}{2*24}=\frac{-12-4\sqrt{15}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{15}}{2*24}=\frac{-12+4\sqrt{15}}{48} $
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