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4x-12/3x+21=-7
We move all terms to the left:
4x-12/3x+21-(-7)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x-12/3x+28=0
We multiply all the terms by the denominator
4x*3x+28*3x-12=0
Wy multiply elements
12x^2+84x-12=0
a = 12; b = 84; c = -12;
Δ = b2-4ac
Δ = 842-4·12·(-12)
Δ = 7632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7632}=\sqrt{144*53}=\sqrt{144}*\sqrt{53}=12\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-12\sqrt{53}}{2*12}=\frac{-84-12\sqrt{53}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+12\sqrt{53}}{2*12}=\frac{-84+12\sqrt{53}}{24} $
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