4x-12=3(3x-4)+x

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Solution for 4x-12=3(3x-4)+x equation: 



4x-12=3(3x-4)+x

We move all terms to the left:

4x-12-(3(3x-4)+x)=0



We calculate terms in parentheses: -(3(3x-4)+x), so:

3(3x-4)+x

We add all the numbers together, and all the variables

x+3(3x-4)

We multiply parentheses

x+9x-12

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We get rid of parentheses

4x-10x+12-12=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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