4x-1=1/2x-4

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Solution for 4x-1=1/2x-4 equation:



4x-1=1/2x-4
We move all terms to the left:
4x-1-(1/2x-4)=0
Domain of the equation: 2x-4)!=0
x∈R
We get rid of parentheses
4x-1/2x+4-1=0
We multiply all the terms by the denominator
4x*2x+4*2x-1*2x-1=0
Wy multiply elements
8x^2+8x-2x-1=0
We add all the numbers together, and all the variables
8x^2+6x-1=0
a = 8; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·8·(-1)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{17}}{2*8}=\frac{-6-2\sqrt{17}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{17}}{2*8}=\frac{-6+2\sqrt{17}}{16} $

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