4x-1=2(3x+4)-8x+15

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Solution for 4x-1=2(3x+4)-8x+15 equation: 



4x-1=2(3x+4)-8x+15

We move all terms to the left:

4x-1-(2(3x+4)-8x+15)=0



We calculate terms in parentheses: -(2(3x+4)-8x+15), so:

2(3x+4)-8x+15

We add all the numbers together, and all the variables

-8x+2(3x+4)+15

We multiply parentheses

-8x+6x+8+15

We add all the numbers together, and all the variables

-2x+23

Back to the equation:

-(-2x+23)



We get rid of parentheses

4x+2x-23-1=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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