4x-1=3(x+1)+(x-4)

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Solution for 4x-1=3(x+1)+(x-4) equation: 



4x-1=3(x+1)+(x-4)

We move all terms to the left:

4x-1-(3(x+1)+(x-4))=0



We calculate terms in parentheses: -(3(x+1)+(x-4)), so:

3(x+1)+(x-4)

We multiply parentheses

3x+(x-4)+3

We get rid of parentheses

3x+x-4+3

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

4x-4x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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