4x-1=3(x+1)+x,x

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Solution for 4x-1=3(x+1)+x,x equation: 



4x-1=3(x+1)+x.x

We move all terms to the left:

4x-1-(3(x+1)+x.x)=0



We calculate terms in parentheses: -(3(x+1)+x.x), so:

3(x+1)+x.x

We multiply parentheses

3x+x.x+3

Back to the equation:

-(3x+x.x+3)



We get rid of parentheses

4x-3x-x.x-3-1=0

We add all the numbers together, and all the variables

x-x.x-4=0

We move all terms containing x to the left, all other terms to the right

x-x.x=4

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