4x-1=3(x+1)x=

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Solution for 4x-1=3(x+1)x= equation: 



4x-1=3(x+1)x=

We move all terms to the left:

4x-1-(3(x+1)x)=0



We calculate terms in parentheses: -(3(x+1)x), so:

3(x+1)x

We multiply parentheses

3x^2+3x

Back to the equation:

-(3x^2+3x)



We get rid of parentheses

-3x^2+4x-3x-1=0

We add all the numbers together, and all the variables

-3x^2+x-1=0

a = -3; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-3)·(-1)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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