4x-1=3x+x2

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Solution for 4x-1=3x+x2 equation: 



4x-1=3x+x2

We move all terms to the left:

4x-1-(3x+x2)=0

We add all the numbers together, and all the variables

-(+3x+x^2)+4x-1=0

We get rid of parentheses

-x^2-3x+4x-1=0

We add all the numbers together, and all the variables

-1x^2+x-1=0

a = -1; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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