4x-2(1-7x)+8=6(1+3x)

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Solution for 4x-2(1-7x)+8=6(1+3x) equation: 



4x-2(1-7x)+8=6(1+3x)

We move all terms to the left:

4x-2(1-7x)+8-(6(1+3x))=0

We add all the numbers together, and all the variables

4x-2(-7x+1)-(6(3x+1))+8=0

We multiply parentheses

4x+14x-(6(3x+1))-2+8=0



We calculate terms in parentheses: -(6(3x+1)), so:

6(3x+1)

We multiply parentheses

18x+6

Back to the equation:

-(18x+6)



We add all the numbers together, and all the variables

18x-(18x+6)+6=0

We get rid of parentheses

18x-18x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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