4x-2(1-x)=3(2+x)-1

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Solution for 4x-2(1-x)=3(2+x)-1 equation:



4x-2(1-x)=3(2+x)-1
We move all terms to the left:
4x-2(1-x)-(3(2+x)-1)=0
We add all the numbers together, and all the variables
4x-2(-1x+1)-(3(x+2)-1)=0
We multiply parentheses
4x+2x-(3(x+2)-1)-2=0
We calculate terms in parentheses: -(3(x+2)-1), so:
3(x+2)-1
We multiply parentheses
3x+6-1
We add all the numbers together, and all the variables
3x+5
Back to the equation:
-(3x+5)
We add all the numbers together, and all the variables
6x-(3x+5)-2=0
We get rid of parentheses
6x-3x-5-2=0
We add all the numbers together, and all the variables
3x-7=0
We move all terms containing x to the left, all other terms to the right
3x=7
x=7/3
x=2+1/3

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