4x-2(2-3X)=3(x-4)-13

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Solution for 4x-2(2-3X)=3(x-4)-13 equation: 



4x-2(2-3x)=3(x-4)-13

We move all terms to the left:

4x-2(2-3x)-(3(x-4)-13)=0

We add all the numbers together, and all the variables

4x-2(-3x+2)-(3(x-4)-13)=0

We multiply parentheses

4x+6x-(3(x-4)-13)-4=0



We calculate terms in parentheses: -(3(x-4)-13), so:

3(x-4)-13

We multiply parentheses

3x-12-13

We add all the numbers together, and all the variables

3x-25

Back to the equation:

-(3x-25)



We add all the numbers together, and all the variables

10x-(3x-25)-4=0

We get rid of parentheses

10x-3x+25-4=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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