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4x-2(2-3x)=3(x-5)-10
We move all terms to the left:
4x-2(2-3x)-(3(x-5)-10)=0
We add all the numbers together, and all the variables
4x-2(-3x+2)-(3(x-5)-10)=0
We multiply parentheses
4x+6x-(3(x-5)-10)-4=0
We calculate terms in parentheses: -(3(x-5)-10), so:We add all the numbers together, and all the variables
3(x-5)-10
We multiply parentheses
3x-15-10
We add all the numbers together, and all the variables
3x-25
Back to the equation:
-(3x-25)
10x-(3x-25)-4=0
We get rid of parentheses
10x-3x+25-4=0
We add all the numbers together, and all the variables
7x+21=0
We move all terms containing x to the left, all other terms to the right
7x=-21
x=-21/7
x=-3
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