4x-2(2-3x)=4(x-4)-6

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Solution for 4x-2(2-3x)=4(x-4)-6 equation: 



4x-2(2-3x)=4(x-4)-6

We move all terms to the left:

4x-2(2-3x)-(4(x-4)-6)=0

We add all the numbers together, and all the variables

4x-2(-3x+2)-(4(x-4)-6)=0

We multiply parentheses

4x+6x-(4(x-4)-6)-4=0



We calculate terms in parentheses: -(4(x-4)-6), so:

4(x-4)-6

We multiply parentheses

4x-16-6

We add all the numbers together, and all the variables

4x-22

Back to the equation:

-(4x-22)



We add all the numbers together, and all the variables

10x-(4x-22)-4=0

We get rid of parentheses

10x-4x+22-4=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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