4x-2(2x-1)=10(x-2)+8

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Solution for 4x-2(2x-1)=10(x-2)+8 equation: 



4x-2(2x-1)=10(x-2)+8

We move all terms to the left:

4x-2(2x-1)-(10(x-2)+8)=0

We multiply parentheses

4x-4x-(10(x-2)+8)+2=0



We calculate terms in parentheses: -(10(x-2)+8), so:

10(x-2)+8

We multiply parentheses

10x-20+8

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We add all the numbers together, and all the variables

-(10x-12)+2=0

We get rid of parentheses

-10x+12+2=0

We add all the numbers together, and all the variables

-10x+14=0

We move all terms containing x to the left, all other terms to the right

-10x=-14

x=-14/-10

x=1+2/5

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