4x-2(3-4x)=2+4(4+8x)

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Solution for 4x-2(3-4x)=2+4(4+8x) equation: 



4x-2(3-4x)=2+4(4+8x)

We move all terms to the left:

4x-2(3-4x)-(2+4(4+8x))=0

We add all the numbers together, and all the variables

4x-2(-4x+3)-(2+4(8x+4))=0

We multiply parentheses

4x+8x-(2+4(8x+4))-6=0



We calculate terms in parentheses: -(2+4(8x+4)), so:

2+4(8x+4)

determiningTheFunctionDomain
4(8x+4)+2

We multiply parentheses

32x+16+2

We add all the numbers together, and all the variables

32x+18

Back to the equation:

-(32x+18)



We add all the numbers together, and all the variables

12x-(32x+18)-6=0

We get rid of parentheses

12x-32x-18-6=0

We add all the numbers together, and all the variables

-20x-24=0

We move all terms containing x to the left, all other terms to the right

-20x=24

x=24/-20

x=-1+1/5

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