4x-2(x+1)=5+3(3-2X)

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Solution for 4x-2(x+1)=5+3(3-2X) equation:



4x-2(x+1)=5+3(3-2x)
We move all terms to the left:
4x-2(x+1)-(5+3(3-2x))=0
We add all the numbers together, and all the variables
4x-2(x+1)-(5+3(-2x+3))=0
We multiply parentheses
4x-2x-(5+3(-2x+3))-2=0
We calculate terms in parentheses: -(5+3(-2x+3)), so:
5+3(-2x+3)
determiningTheFunctionDomain 3(-2x+3)+5
We multiply parentheses
-6x+9+5
We add all the numbers together, and all the variables
-6x+14
Back to the equation:
-(-6x+14)
We add all the numbers together, and all the variables
2x-(-6x+14)-2=0
We get rid of parentheses
2x+6x-14-2=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2

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