4x-2(x+1)=5+3(3-3x)

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Solution for 4x-2(x+1)=5+3(3-3x) equation: 



4x-2(x+1)=5+3(3-3x)

We move all terms to the left:

4x-2(x+1)-(5+3(3-3x))=0

We add all the numbers together, and all the variables

4x-2(x+1)-(5+3(-3x+3))=0

We multiply parentheses

4x-2x-(5+3(-3x+3))-2=0



We calculate terms in parentheses: -(5+3(-3x+3)), so:

5+3(-3x+3)

determiningTheFunctionDomain
3(-3x+3)+5

We multiply parentheses

-9x+9+5

We add all the numbers together, and all the variables

-9x+14

Back to the equation:

-(-9x+14)



We add all the numbers together, and all the variables

2x-(-9x+14)-2=0

We get rid of parentheses

2x+9x-14-2=0

We add all the numbers together, and all the variables

11x-16=0

We move all terms containing x to the left, all other terms to the right

11x=16

x=16/11

x=1+5/11

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