4x-2(x+3)=2+5(3-4x)

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Solution for 4x-2(x+3)=2+5(3-4x) equation: 



4x-2(x+3)=2+5(3-4x)

We move all terms to the left:

4x-2(x+3)-(2+5(3-4x))=0

We add all the numbers together, and all the variables

4x-2(x+3)-(2+5(-4x+3))=0

We multiply parentheses

4x-2x-(2+5(-4x+3))-6=0



We calculate terms in parentheses: -(2+5(-4x+3)), so:

2+5(-4x+3)

determiningTheFunctionDomain
5(-4x+3)+2

We multiply parentheses

-20x+15+2

We add all the numbers together, and all the variables

-20x+17

Back to the equation:

-(-20x+17)



We add all the numbers together, and all the variables

2x-(-20x+17)-6=0

We get rid of parentheses

2x+20x-17-6=0

We add all the numbers together, and all the variables

22x-23=0

We move all terms containing x to the left, all other terms to the right

22x=23

x=23/22

x=1+1/22

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