4x-2(x+4)=5x-4(x-3)

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Solution for 4x-2(x+4)=5x-4(x-3) equation: 



4x-2(x+4)=5x-4(x-3)

We move all terms to the left:

4x-2(x+4)-(5x-4(x-3))=0

We multiply parentheses

4x-2x-(5x-4(x-3))-8=0



We calculate terms in parentheses: -(5x-4(x-3)), so:

5x-4(x-3)

We multiply parentheses

5x-4x+12

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We add all the numbers together, and all the variables

2x-(x+12)-8=0

We get rid of parentheses

2x-x-12-8=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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