4x-2(x-3)+12=20

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Solution for 4x-2(x-3)+12=20 equation: 



4x-2(x-3)+12=20

We move all terms to the left:

4x-2(x-3)+12-(20)=0

We add all the numbers together, and all the variables

4x-2(x-3)-8=0

We multiply parentheses

4x-2x+6-8=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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