4x-2(x-3)=5+2(1+3x)

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Solution for 4x-2(x-3)=5+2(1+3x) equation: 



4x-2(x-3)=5+2(1+3x)

We move all terms to the left:

4x-2(x-3)-(5+2(1+3x))=0

We add all the numbers together, and all the variables

4x-2(x-3)-(5+2(3x+1))=0

We multiply parentheses

4x-2x-(5+2(3x+1))+6=0



We calculate terms in parentheses: -(5+2(3x+1)), so:

5+2(3x+1)

determiningTheFunctionDomain
2(3x+1)+5

We multiply parentheses

6x+2+5

We add all the numbers together, and all the variables

6x+7

Back to the equation:

-(6x+7)



We add all the numbers together, and all the variables

2x-(6x+7)+6=0

We get rid of parentheses

2x-6x-7+6=0

We add all the numbers together, and all the variables

-4x-1=0

We move all terms containing x to the left, all other terms to the right

-4x=1

x=1/-4

x=-1/4

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