4x-2(x-3)=x-(2x-1)=4

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Solution for 4x-2(x-3)=x-(2x-1)=4 equation: 



4x-2(x-3)=x-(2x-1)=4

We move all terms to the left:

4x-2(x-3)-(x-(2x-1))=0

We multiply parentheses

4x-2x-(x-(2x-1))+6=0



We calculate terms in parentheses: -(x-(2x-1)), so:

x-(2x-1)

We get rid of parentheses

x-2x+1

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We add all the numbers together, and all the variables

2x-(-1x+1)+6=0

We get rid of parentheses

2x+1x-1+6=0

We add all the numbers together, and all the variables

3x+5=0

We move all terms containing x to the left, all other terms to the right

3x=-5

x=-5/3

x=-1+2/3

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