4x-2(x-4)=-8+4x+2

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Solution for 4x-2(x-4)=-8+4x+2 equation: 



4x-2(x-4)=-8+4x+2

We move all terms to the left:

4x-2(x-4)-(-8+4x+2)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(4x-6)=0

We multiply parentheses

4x-2x-(4x-6)+8=0

We get rid of parentheses

4x-2x-4x+6+8=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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