4x-2(x-4)=-8+5x-2

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Solution for 4x-2(x-4)=-8+5x-2 equation:



4x-2(x-4)=-8+5x-2
We move all terms to the left:
4x-2(x-4)-(-8+5x-2)=0
We add all the numbers together, and all the variables
4x-2(x-4)-(5x-10)=0
We multiply parentheses
4x-2x-(5x-10)+8=0
We get rid of parentheses
4x-2x-5x+10+8=0
We add all the numbers together, and all the variables
-3x+18=0
We move all terms containing x to the left, all other terms to the right
-3x=-18
x=-18/-3
x=+6

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