4x-2(x-4)=2+4x-2

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Solution for 4x-2(x-4)=2+4x-2 equation: 



4x-2(x-4)=2+4x-2

We move all terms to the left:

4x-2(x-4)-(2+4x-2)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(+4x)=0

We multiply parentheses

4x-2x-(+4x)+8=0

We get rid of parentheses

4x-2x-4x+8=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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