4x-2(x-4)=6+4x+10

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Solution for 4x-2(x-4)=6+4x+10 equation: 



4x-2(x-4)=6+4x+10

We move all terms to the left:

4x-2(x-4)-(6+4x+10)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(4x+16)=0

We multiply parentheses

4x-2x-(4x+16)+8=0

We get rid of parentheses

4x-2x-4x-16+8=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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