4x-2(x-4)=7+4x+1

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Solution for 4x-2(x-4)=7+4x+1 equation: 



4x-2(x-4)=7+4x+1

We move all terms to the left:

4x-2(x-4)-(7+4x+1)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(4x+8)=0

We multiply parentheses

4x-2x-(4x+8)+8=0

We get rid of parentheses

4x-2x-4x-8+8=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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