4x-2(x-4)=8+5x+1

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Solution for 4x-2(x-4)=8+5x+1 equation: 



4x-2(x-4)=8+5x+1

We move all terms to the left:

4x-2(x-4)-(8+5x+1)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(5x+9)=0

We multiply parentheses

4x-2x-(5x+9)+8=0

We get rid of parentheses

4x-2x-5x-9+8=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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