4x-2(x-4)=8+5x+10

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Solution for 4x-2(x-4)=8+5x+10 equation: 



4x-2(x-4)=8+5x+10

We move all terms to the left:

4x-2(x-4)-(8+5x+10)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(5x+18)=0

We multiply parentheses

4x-2x-(5x+18)+8=0

We get rid of parentheses

4x-2x-5x-18+8=0

We add all the numbers together, and all the variables

-3x-10=0

We move all terms containing x to the left, all other terms to the right

-3x=10

x=10/-3

x=-3+1/3

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