4x-2(x-5)=8+4x+10

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Solution for 4x-2(x-5)=8+4x+10 equation:



4x-2(x-5)=8+4x+10
We move all terms to the left:
4x-2(x-5)-(8+4x+10)=0
We add all the numbers together, and all the variables
4x-2(x-5)-(4x+18)=0
We multiply parentheses
4x-2x-(4x+18)+10=0
We get rid of parentheses
4x-2x-4x-18+10=0
We add all the numbers together, and all the variables
-2x-8=0
We move all terms containing x to the left, all other terms to the right
-2x=8
x=8/-2
x=-4

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