4x-20+20=200/2x

Solution for 4x-20+20=200/2x equation:

4x-20+20=200/2x

We move all terms to the left:

4x-20+20-(200/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-(+200/2x)-20+20=0

We add all the numbers together, and all the variables

4x-(+200/2x)=0

We get rid of parentheses

4x-200/2x=0

We multiply all the terms by the denominator


4x*2x-200=0

Wy multiply elements

8x^2-200=0

a = 8; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·8·(-200)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*8}=\frac{-80}{16}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*8}=\frac{80}{16}
=5
$