4x-27=-3y;9x-5y=2

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x+3y=14

Solution for 4x-27=-3y;9x-5y=2 system of equations: 


  • /| 4*x-(-3*y)-27 = 0| 9*x-(5*y)-2 = 0
  • We try to solve the equation: 4*x-(-3*y)-27 = 0
  • 4*x+3*y-27 = 0 // - 4*x-27
  • 3*y = -(4*x-27) // : 3
  • y = (-(4*x-27))/3
  • y = (27-(4*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 9*x-(5*((27-(4*x))/3))-2 = 0| y = (27-(4*x))/3
  • (-1*5*(27-4*x))/3+9*x-2 = 0
  • 47/3*x-45-2 = 0
  • 47/3*x-47 = 0
  • 47/3*x-47 = 0 // + 47
  • 47/3*x = 47 // : 47/3
  • x = 47/47/3
  • x = 3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (27-(4*x))/3: 
  • y = (27-(3*4))/3
  • y = (27-12)/3
  • y = 15/3
  • y = 5
  • We get a system of equations:
  • /| y = 5| x = 3

 

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