4x-2=3*(x-3)+12

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Solution for 4x-2=3*(x-3)+12 equation: 



4x-2=3(x-3)+12

We move all terms to the left:

4x-2-(3(x-3)+12)=0



We calculate terms in parentheses: -(3(x-3)+12), so:

3(x-3)+12

We multiply parentheses

3x-9+12

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

4x-3x-3-2=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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