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4x-2=5/2x
We move all terms to the left:
4x-2-(5/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+5/2x)-2=0
We get rid of parentheses
4x-5/2x-2=0
We multiply all the terms by the denominator
4x*2x-2*2x-5=0
Wy multiply elements
8x^2-4x-5=0
a = 8; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·8·(-5)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{11}}{2*8}=\frac{4-4\sqrt{11}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{11}}{2*8}=\frac{4+4\sqrt{11}}{16} $
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