4x-2x(x+4)=3(2x+4)

Solution for 4x-2x(x+4)=3(2x+4) equation:

4x-2x(x+4)=3(2x+4)

We move all terms to the left:

4x-2x(x+4)-(3(2x+4))=0

We multiply parentheses

-2x^2+4x-8x-(3(2x+4))=0


We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)


We add all the numbers together, and all the variables

-2x^2-4x-(6x+12)=0

We get rid of parentheses

-2x^2-4x-6x-12=0

We add all the numbers together, and all the variables

-2x^2-10x-12=0

a = -2; b = -10; c = -12;
Δ = b2-4ac
Δ = -102-4·(-2)·(-12)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*-2}=\frac{8}{-4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*-2}=\frac{12}{-4}
=-3
$