4x-3(2-3x)=4(x-5)-13

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Solution for 4x-3(2-3x)=4(x-5)-13 equation: 



4x-3(2-3x)=4(x-5)-13

We move all terms to the left:

4x-3(2-3x)-(4(x-5)-13)=0

We add all the numbers together, and all the variables

4x-3(-3x+2)-(4(x-5)-13)=0

We multiply parentheses

4x+9x-(4(x-5)-13)-6=0



We calculate terms in parentheses: -(4(x-5)-13), so:

4(x-5)-13

We multiply parentheses

4x-20-13

We add all the numbers together, and all the variables

4x-33

Back to the equation:

-(4x-33)



We add all the numbers together, and all the variables

13x-(4x-33)-6=0

We get rid of parentheses

13x-4x+33-6=0

We add all the numbers together, and all the variables

9x+27=0

We move all terms containing x to the left, all other terms to the right

9x=-27

x=-27/9

x=-3

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