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4x-3(2x-3)=3(x-1)-2(3x-2)
We move all terms to the left:
4x-3(2x-3)-(3(x-1)-2(3x-2))=0
We multiply parentheses
4x-6x-(3(x-1)-2(3x-2))+9=0
We calculate terms in parentheses: -(3(x-1)-2(3x-2)), so:We add all the numbers together, and all the variables
3(x-1)-2(3x-2)
We multiply parentheses
3x-6x-3+4
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
-2x-(-3x+1)+9=0
We get rid of parentheses
-2x+3x-1+9=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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