4x-3(2x-3)=3(x-1)-2(3x-2)

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Solution for 4x-3(2x-3)=3(x-1)-2(3x-2) equation: 



4x-3(2x-3)=3(x-1)-2(3x-2)

We move all terms to the left:

4x-3(2x-3)-(3(x-1)-2(3x-2))=0

We multiply parentheses

4x-6x-(3(x-1)-2(3x-2))+9=0



We calculate terms in parentheses: -(3(x-1)-2(3x-2)), so:

3(x-1)-2(3x-2)

We multiply parentheses

3x-6x-3+4

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

-2x-(-3x+1)+9=0

We get rid of parentheses

-2x+3x-1+9=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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