4x-3(3-2x)=2(x-4)+6x+7

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Solution for 4x-3(3-2x)=2(x-4)+6x+7 equation: 



4x-3(3-2x)=2(x-4)+6x+7

We move all terms to the left:

4x-3(3-2x)-(2(x-4)+6x+7)=0

We add all the numbers together, and all the variables

4x-3(-2x+3)-(2(x-4)+6x+7)=0

We multiply parentheses

4x+6x-(2(x-4)+6x+7)-9=0



We calculate terms in parentheses: -(2(x-4)+6x+7), so:

2(x-4)+6x+7

We add all the numbers together, and all the variables

6x+2(x-4)+7

We multiply parentheses

6x+2x-8+7

We add all the numbers together, and all the variables

8x-1

Back to the equation:

-(8x-1)



We add all the numbers together, and all the variables

10x-(8x-1)-9=0

We get rid of parentheses

10x-8x+1-9=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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