4x-3(3-2x)=3(x-5)-15

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Solution for 4x-3(3-2x)=3(x-5)-15 equation: 



4x-3(3-2x)=3(x-5)-15

We move all terms to the left:

4x-3(3-2x)-(3(x-5)-15)=0

We add all the numbers together, and all the variables

4x-3(-2x+3)-(3(x-5)-15)=0

We multiply parentheses

4x+6x-(3(x-5)-15)-9=0



We calculate terms in parentheses: -(3(x-5)-15), so:

3(x-5)-15

We multiply parentheses

3x-15-15

We add all the numbers together, and all the variables

3x-30

Back to the equation:

-(3x-30)



We add all the numbers together, and all the variables

10x-(3x-30)-9=0

We get rid of parentheses

10x-3x+30-9=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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