4x-3(3-2x)=4(x-5)-25

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Solution for 4x-3(3-2x)=4(x-5)-25 equation: 



4x-3(3-2x)=4(x-5)-25

We move all terms to the left:

4x-3(3-2x)-(4(x-5)-25)=0

We add all the numbers together, and all the variables

4x-3(-2x+3)-(4(x-5)-25)=0

We multiply parentheses

4x+6x-(4(x-5)-25)-9=0



We calculate terms in parentheses: -(4(x-5)-25), so:

4(x-5)-25

We multiply parentheses

4x-20-25

We add all the numbers together, and all the variables

4x-45

Back to the equation:

-(4x-45)



We add all the numbers together, and all the variables

10x-(4x-45)-9=0

We get rid of parentheses

10x-4x+45-9=0

We add all the numbers together, and all the variables

6x+36=0

We move all terms containing x to the left, all other terms to the right

6x=-36

x=-36/6

x=-6

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